Tan32+tan13+tan32tan13=1
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Rashmi Bajpayee 8 years, 9 months ago
tan 32o + tan 13o + tan 32o.tan13o = 1
tan 32<font size="2">o</font> + tan 13<font size="2">o</font> = 1 - tan 32<font size="2">o</font>.tan13<font size="2">o</font>
(tan 32<font size="2">o</font> + tan 13<font size="2">o)/(</font>1 - tan 32<font size="2">o</font>.tan13<font size="2">o</font><font size="2">) = 1</font>
<font size="2">tan (32o + 13o) = 1 [Since tan (A + B) = (tan A + tan B)/(1 - tan A. tan B)]</font>
<font size="2">tan 45o = 1</font>
<font size="2">1 = 1 [Since tan 45o = 1]</font>
<font size="2">Hence proved.</font>
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