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Last uear paper 1 ka 6 restion

Posted by Asif Ansari 8 years, 7 months ago

CBSE > Class 09 > Mathematics

1 answers

Anrag Singh 8 years, 7 months ago

F(x)=2X³-KX²-X-2 P(X)=2X-1 Then zero of p(x) be 2x-1=0 2x=0+1 2x=1 x=1/2 So, F(1/2)=2×(1/2)³-k×(1/2)²-1/2-2=0 F(1/2)=2×1/8 - 1/4k - 1/2 - 2=0 F(1/2)=4 - 1/4k - 1/2 - 2=0 F(1/2)=4 - 1/2 - 2 -1/4k=0 F(1/2)=3/2 - 1/4k=0. (4 - 1/2 - 2=3/2) F(1/2)= -1/4k=-3/2 K= -3/2+1/4 K=-2/4 answer.

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CBSE > Class 09 > Mathematics

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CBSE > Class 09 > Mathematics