if roots of equation (a-b)x2+(b-c)x+(c-a)=0,prove that …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Khalid Moammed 8 years, 2 months ago
- 3 answers
Shweta Gulati 3 years ago
The question must be, if roots of equation (a-b)x2+(b-c)x+(c-a)=0 are equal , prove that b+c = 2a.
Using Discriminant,
D = B2-4AC as compared with the general quadratic equation Ax2+Bx+C=0
so, A = a-b
B = b-c
C = c-a
For roots to be equal, D=0
(b-c)2 - 4(a-b)(c-a) =0
b2+c2-2bc -4(ac-a2-bc+ab) =0
b2+c2-2bc -4ac+4a2+4bc-4ab=0
4a2+b2+c2+2bc-4ab-4ac=0
(2a-b-c)2=0
i.e. 2a-b-c =0
2a= b+c
Related Questions
Posted by Parinith Gowda Ms 9 months, 1 week ago
- 0 answers
Posted by Hari Anand 6 months ago
- 0 answers
Posted by Lakshay Kumar 5 months, 3 weeks ago
- 0 answers
Posted by S Prajwal 3 months, 3 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 9 months, 1 week ago
- 1 answers
Posted by Vanshika Bhatnagar 9 months, 1 week ago
- 2 answers
Posted by Kanika . 7 months, 2 weeks ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Pankaj Sawarbandhe 4 years, 1 month ago
0Thank You