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The angle of depression of the …

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The angle of depression of the top and bottom of a building 50m high as observed from the top of a tower are 30°and 60°, respectively. Find the high of the tower and also the horizontal distance between the building and the tower.

Posted by Naveen Singh 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Garima Gupta 7 years, 9 months ago

Let the height of the tower is h and horizontal distance between building and tower is x. X is equals to under root 3(h-50) H equals to under root 3x. .........1 Put the value of x then we get h is equal to 75 m Now put h in equation 1 then x is equal to 25 multiply under root 3.

Rex Cartin 7 years, 9 months ago

In ΔBTP, tan 30° = TP/BP 1/√3 = TP/BP BP = TP√3 In ΔGTR, tan 60° = TR/GR √3 = TR/GR GR = TR/√3 As BP = GR TP√3 = TR/√3 3 TP = TP + PR 2 TP = BG TP = 50/2 m = 25 m Now, TR = TP + PR TR = (25 + 50) m Height of tower = TR = 75 m Distance between building and tower = GR = TR/√3 GR = 75/√3 m = 25√3 m I Hope this helps you

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