Find the range of the function …
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Posted by Sourav Keshri 8 years, 9 months ago
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Naveen Sharma 8 years, 9 months ago
Ans. To Find Range,
\(Let \space y = {1 \over 1-x^2}\)
\(=> {1-x^2} = {1\over y} \)
\(=> x^2 ={1-{1\over y}}\)
\(=> x^2 = {y-1\over y}\)
\(=> x= {\sqrt{y-1\over y}}\)
\(Now,\space this \space is \space defined \space for \space {y-1\over y} \geq 0 \space except \space y \neq 0\)
\(y \in (-\infty , 0) \cup [1, \infty)\)
So Domain is \((-\infty , 0) \cup [1, \infty)\)
0Thank You