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In triangle PQR, S is any point on the side QR of triangle PQR. Prove that PQ+QR+RP is greater than 2 PS

Posted by Gargi Tanwar 7 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Nivedhini Pari 7 years, 10 months ago

Use the theorem,the sum of two sides is always greater than the 3rd side. Now,in triangle PQS,PQ+QS>PS -eq 1 In triangle PRS,PR+SR>PS -eq 2 Now add EQ. 1 and EQ.2. So, PQ+QS+PR+SR>PS+PS PQ+PR+QR>2PS Thus proved

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