Water in a canal 5.4m wide …

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Sia ? 6 years, 4 months ago
According to the question,we have the following information.
Water flow in 1 hr = Area of cross-section {tex}\times{/tex} Speed of water
{tex}= 5 \cdot 4 \times 1 \cdot 8 \times 25000 \mathrm { m } ^ { 3 }{/tex}=54×18×250
Water flow in 40 minutes
{tex}= 54 \times 6 \times 500 \mathrm { m } ^ { 3 }{/tex}
Irrigated area {tex}\times \frac { 10 } { 100 } = 54 \times 6 \times 500{/tex}
Irrigated area {tex}= 54 \times 6 \times 500 \times 10{/tex}
{tex}= 1620000 \mathrm { m } ^ { 2}{/tex}
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