A bat emits ultrasond wave of …
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Shweta Gulati 7 years, 2 months ago
Speed of sound = 350 m/s
Echo time = 0.6 s
i.e. time = 0.6/2 =0.3s
Distance of the bat and obstacle = speed X time
= 350 X 0.3 = 105 m
\({\lambda }\)= velocity / frequency
= 350/30000 = 11.7 X 10-3 m
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