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For what value of k+9 2k-1and …

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For what value of k+9 2k-1and 2k+7be the consecutive terms of an Ap

    • Posted by Akash Darur 7 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 8 answers

    Nishika Agrawal 7 years, 9 months ago

    They are in ap therefore, common difference is same. (2k-1)-(k+9)=(2k+7)-(2k-1) 2k-1-k-9=2k+7-2k+1 K-10=8 K=8+10 K=18

    0Thank You

    Vaibhav Jain 7 years, 9 months ago

    Whose answer is correct?

    1Thank You

    Vaibhav Jain 7 years, 9 months ago

    2b = a+c. (K+9)+(2k+7) = 2(2 k+1). 3k+16 = 4k+2. -k = -14, k= 14

    0Thank You

    Dhruv Gupta 7 years, 9 months ago

    Sincecthey are in ap therefore there diff will be same 2k-1-(k+9)=2k+7-(2k-1) k=18

    0Thank You

    Vaibhav Jain 7 years, 9 months ago

    Just put identity : 2b= a+ c Answer: 14

    0Thank You

    Hitesh Kumar 7 years, 9 months ago

    4

    0Thank You

    Hitesh Kumar 7 years, 9 months ago

    6

    1Thank You

    Sathish Kumar 7 years, 9 months ago

    a+c =2b k+9+2k+7=2×2k-1 3k+16=4k-4 K=20

    0Thank You

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