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In a hot water heating system , there is a cylinderical pipe of length 28m and diameter 5cm . Find the total radiating surface in the system

Posted by Jayant Kumar 8 years, 7 months ago

CBSE > Class 09 > Mathematics

1 answers

Nitin Kumawat 8 years, 7 months ago

Total radiating surface=curved surface area of cylinder

{tex}=2\pi rh{/tex}

h=28m and r={tex}\frac52cm=\frac 5{200}m{/tex}

Total radiating surface={tex}2\times \frac{22}7\times\frac5{200}\times28{/tex}

{tex}=4.4m^2{/tex}

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