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Manish Gandhi 8 years, 9 months ago
Total arrangements possible are 7P7 = 7! = 5040
There are 2 vowels & 5 cosonants => there is only one way when the given condition will not meet & that is when both these vowels will occupy the odd places. Now, the no. of ways it is possible = 4P2 * 5P5 = 12 * 120 = 1440
=> Total words which can be formed in the required fashion are 5040-1440 = 3600 (Answer)
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