solve for x and y. 2(3x-y)=5xy …
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Sia ? 6 years ago
2(3x - y) = 5xy .(i)
2(x + 3y) = 5xy ..(ii)
Divide eqns. (i) and (ii) by xy,
6y−2x=5 ....(iii)
and 2y+6x=5 .....(iv)
Let 1y=a and 1x=b
then equations (iii) and (iv) become
6a - 2 b = 5 ......(v)
2a -6b = 5 ...(vi)
Multiplying eqn. (v) by 3 and then adding with eqn. (vi),
18a - 6b + 2a - 6b = 15 + 5
20a = 20
∴ a=1
Substituting this value of a in eqn. (v),
b=12
Now 1y=a=1
or, y=1
and 1x=b=12
or, x=2
Hence, x = 2, y = 1
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