Derivation for coulomb law

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sangam Tripathi 7 years, 10 months ago
- 5 answers
Aparna Nair 7 years, 10 months ago
It states that force of attraction and repulsion between two charges is directly proportional to product of charges are inversely proportional to square of distance between them.
F proportional to q1.q2
F proportional to 1/r^2
According to the law
That is
F proportional to q1.q2 /r^2
To remove the proportionality sign we substitute k which is equal to
1/4¶€°=k
[ which is equal to 9×10^9 Nm^2 /C^2]
AND €°=8.854×10^-19
That is
F=1/4¶€° [ q1.q2 /r^2]
If €r Is relative permittivity of a medium (in air value of €r is equal to 1)
F=1/4¶€°€r [ q1.q2 /r^2]
P. S:
¶=pi
€°= Epsilon 0
€r= Epsilon r
K= constant of proportionality
And absolute permittivity in free space = to
1/4¶€°=k
☺️☺️☺️
Related Questions
Posted by Khushbu Otti 1 year, 5 months ago
- 0 answers
Posted by Aniket Mahajan 10 months ago
- 0 answers
Posted by Anterpreet Kaur 1 year, 5 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Aparna Nair 7 years, 10 months ago
0Thank You