Derivation for coulomb law
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Posted by Sangam Tripathi 8 years, 1 month ago
- 5 answers
Aparna Nair 8 years, 1 month ago
It states that force of attraction and repulsion between two charges is directly proportional to product of charges are inversely proportional to square of distance between them.
F proportional to q1.q2
F proportional to 1/r^2
According to the law
That is
F proportional to q1.q2 /r^2
To remove the proportionality sign we substitute k which is equal to
1/4¶€°=k
[ which is equal to 9×10^9 Nm^2 /C^2]
AND €°=8.854×10^-19
That is
F=1/4¶€° [ q1.q2 /r^2]
If €r Is relative permittivity of a medium (in air value of €r is equal to 1)
F=1/4¶€°€r [ q1.q2 /r^2]
P. S:
¶=pi
€°= Epsilon 0
€r= Epsilon r
K= constant of proportionality
And absolute permittivity in free space = to
1/4¶€°=k
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Aparna Nair 8 years, 1 month ago
0Thank You