sin thita + cos thita = …
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Samir Kumar Basu 7 years, 10 months ago
sinθ+cosθ=√2⇒1√2sinθ+1√2cosθ=1⇒cos(θ−π4)=cos0⇒θ−π4=2nπ[n∈setofintegers]⇒θ=2nπ+π4
sinθ=sin(2nπ+π4)=sinπ4=1√2
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