sin thita + cos thita = …
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Samir Kumar Basu 8 years, 3 months ago
{tex}\begin{array}{l}\sin\theta+\cos\theta=\sqrt2\\\Rightarrow\frac1{\sqrt2}\sin\theta+\frac1{\sqrt2}\cos\theta=1\\\Rightarrow\cos\left(\theta-\frac\pi4\right)=\cos\;0\\\Rightarrow\theta-\frac\pi4=2n\pi\;\;\;\;\;\lbrack n\in set\;of\;integers\;\rbrack\\\Rightarrow\theta=2n\pi\;+\frac\pi4\end{array}{/tex}
{tex}\sin\theta=\sin\;\left(2n\pi\;+\frac\pi4\right)\;\;\;=\sin\frac\pi4=\frac1{\sqrt2}{/tex}
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