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Derive Kepler 3th low

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Derive Kepler 3th low

    • Posted by Raja Chouhan 8 years, 1 month ago

    CBSE > Class 11 > Physics
    • 1 answers

    Himanshu Tiwari 8 years, 1 month ago

    First T=πab/dA/dt T=πab/L/2m T=2mπab/L T^2=4π^2a^2b^2/L^2 Now b^2=al T^2=a^3

    1Thank You

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