a path 2.5cm wide runs along …
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a path 2.5cm wide runs along inside the boundary of a park whose length and breath are 72m and 43m respectively find the are of path and cost of levelling it at rupees 1.25per sq. m
Posted by Shahista Anjum 8 years, 4 months ago
- 2 answers
Rashmi Bajpayee 8 years, 4 months ago
In the quesiton, please check, the path should be 2.5 m wide instead of 2.5 cm.
Area of park = 72 m x 43 m = 3096 sq. m
Area of park including width of footpath = (72 + 2.5 + 2.5) x (43 + 2.5 + 2.5) = 77 m x 48 m = 3696 sq. m
Now,
Area of Path = 3696 - 3096 = 600 sq. m
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Naveen Sharma 8 years, 4 months ago
Ans. [Image Here ]
in the given fiqure, the shaded portion is path. Let PQRS be the park whose
Length (L) = 72 m
Breadth (B) = 43 m
Area of Park = 72 * 43 = 3096 m2
Length of Field ABCD (L1) = 72 - (2.5+2.5) = 67 m
Breadth of Field ABCD (B1) = 43 - (2.5+2.5) = 38 m
Area of Field ABCD = 67 * 38 = 2546 m2
Area of Path = Area of Park PQRS - Area of Field ABCD
=> Area of Bath = 3096 - 2546 = 550 m2
Rate of Levelling = Rs. 1.25 per m2
Cost of Levelling the Path = 550 * 1.25 = Rs. 687.50
0Thank You