Metal spheres, each of radius 2cm, …
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Metal spheres, each of radius 2cm, are packed into a rectangular box of dimensions 16cm×8cm×8cm. When 16 spheres are packed in the box, it is filled with preservative liquid. Find the volume of this liquid to the nearest integer.
Posted by Sadhna Kashyap 8 years, 10 months ago
- 2 answers
Naveen Sharma 8 years, 10 months ago
Ans. Radius of Sphere Ball = 2cm
Total Nunber of Balls = 16
Volume of 16 sphere Balls = 16 *(22/7)*(4/3)*(2)3= (16 * 88 * 8)/21
=> 536.38 cm3
Volume of Rectanglular Box = \({16\times 8\times8} = 1024cm^3\)
Volume of Preservative Liquid = Volume of Box -Volume of Sphere Balls
=> 1024 - 536.38 = 487.62cm3
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Shweta Gulati 8 years, 10 months ago
Volume of rectangular box= l X b X h
= 16 X 8 X 8 = 1024 cm3
Volume of a sphere = \( {4 \pi r^3 \over 3}\)
= \( {4 \times 22 \times2\times 2\times2 \over 3\times7}\)
= 33.52 cm3
Volume of 16 spheres = 16 X 33.52
= 536.38 cm3
Volume of liquid in box = Volume of box- Volume of 16 spheres
= 1024-536.38 = 487.62 cm3 = 488 cm3 (to the nearest integer)
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