If 6x=secA and 6/x=tanA then find …
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Sia ? 6 years ago
We have,
6x = sec θ........(i)
and 6x=tanθ ........(ii)
Adding (i) and (ii), we get
6(x+1x)=(secθ+tanθ).......(iii)
Subtracting (ii) from (i), we get
6(x−1x)=(secθ−tanθ)........(iv)
Multiplying the corresponding sides of (iii) and (iv), we get
36(x2−1x2)=(sec2θ−tan2θ)=1
⇒9(x2−1x2)=14
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