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If 6x=secA and 6/x=tanA then find …

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If 6x=secA and 6/x=tanA then find value of 9(x^2-1/x^2)
  • 1 answers

Sia ? 6 years ago

We have,
6x = sec θ........(i)
and 6x=tanθ ........(ii)
Adding (i) and (ii), we get
6(x+1x)=(secθ+tanθ).......(iii)
Subtracting (ii) from (i), we get
6(x1x)=(secθtanθ)........(iv)
Multiplying the corresponding sides of (iii) and (iv), we get
36(x21x2)=(sec2θtan2θ)=1
9(x21x2)=14

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