Find dy/dx of log. Log sin …
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Naveen Sharma 8 years, 10 months ago
Ans. If question is: log (log sin x1/2)
then according to Chain rule
\({dy\over dx} = { 1\over log( sin x^{1\over 2})} \times { 1 \over sin (x)^{1\over2}} \times cos (x)^{1\over 2}\times {1\over2\sqrt x}\)
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