If a+b+c=14, a2+b2+c2=74 and a3+b3+c3=434 find …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Himanshi M 8 years, 7 months ago
- 2 answers
Rashmi Bajpayee 8 years, 7 months ago
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) => (14)2 = 74 + 2(ab + bc + ca) => ab + bc + ca = 122 / 2 = 61
Again, using a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 + ab + bc + ca)
=> 434 - 3abc = 14 (74 - 61)
=> -3abc = -252
=> abc = 84
Related Questions
Posted by Duruvan Sivan 9 months, 1 week ago
- 0 answers
Posted by Akhilesh Patidar 9 months, 1 week ago
- 0 answers
Posted by T Prudhvi 6 months, 2 weeks ago
- 0 answers
Posted by Sheikh Alfaz 3 months, 3 weeks ago
- 0 answers
Posted by Alvin Thomas 1 week, 6 days ago
- 0 answers
Posted by Savitha Savitha 9 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Manish Gandhi 8 years, 4 months ago
We know, (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) => (14)2 = 74 + 2(ab + bc + ca) => ab + bc + ca = 122 / 2 = 61
Again, using a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - ab - bc - ca)
434 - 3abc = 14 (74 - 61)
434 - 3abc = 14 (13)
434 - 3abc = 182
3abc = 434 - 182 = 252
Abc = 252/3 = 84 (Answer)
0Thank You