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7sin^2A+3cos^2A=4 show that tanA=1/root3

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7sin^2A+3cos^2A=4 show that tanA=1/root3

    • Posted by Priya Patel 8 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Naveen Sharma 8 years, 3 months ago

    {tex}7sin^2A+3cos^2A=4{/tex}

    {tex}=> 4sin^2A+ 3sin^2A+3cos^2A=4{/tex}

    {tex}=> 4sin^2A+ 3(sin^2A+cos^2A)=4{/tex}

    {tex}=> 4sin^2A+ 3=4{/tex}
    {tex}=> 4sin^2A = 1 {/tex}

    {tex}=> sin^2A = {1\over 4} {/tex}

    {tex}=> sinA = {1\over 2}{/tex}

    {tex}=> sinA = sin 30^o{/tex}

    {tex}=> A = 30^o{/tex}

    So {tex}tan A= tan 30^o = {1\over \sqrt 3}{/tex}

    3Thank You

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