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What is the value of sin18°

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What is the value of sin18°

    • Posted by Rizwan Choudhary 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 3 answers

    Kumar Rahul 7 years, 10 months ago

    √5-1/4

    0Thank You

    Rizwan Choudhary 7 years, 10 months ago

    Let θ=18° 5θ=90° 2θ+3θ=90° Sin2θ=sin(90°-3θ) Sin2θ=cos3θ 2sinθcosθ=4cos(cube)θ-3cosθ 2sinθ=4cos(square)θ-3 2sinθ=4(1-sin(square)θ)-3 4sin(square)θ+2sinθ-1=0 (Sinθ=sin18°) Sin18°=-2+_under root 4+16÷2×4 Sin18°=under root 5-1÷4

    0Thank You

    Riya Chaudhary 7 years, 10 months ago

    Can not be able to find

    1Thank You

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