Find dy/dx yx = xy
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Naveen Sharma 8 years, 4 months ago
Ans. yx = xy
Take log both side, we get
log yx = log xy
=> x log y = y log x
differentiate w.r.t x, we get
=> x1ydydx+logy=y1x+logxdydx
=> xydydx−logxdydx=yx−logy
=> (xy−logx)dydx=yx−logy
=> dydx=(yx−logy)(xy−logx)
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