No products in the cart.

Find the equation of the circle …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Find the equation of the circle with radius 5 whose center lie on x axis and passes through the point 2,3
  • 1 answers

Jai Jai 7 years, 10 months ago

Centerville is on x axis so center is (x,0) and passses through point (2,3) it means 2,3 is on circumference so Distance from center to circumference is the radius. Then, √(X-0)^2 +(3-0)^2 = (5) X^2 +3^2=5^2 X^2+9=25 X^2=25-9=16 X=√16=4 X=4
https://examin8.com Test

Related Questions

Express the complex number i-39
  • 0 answers
Ch 1 ke questions
  • 1 answers
2nC2:nC3=33:10
  • 0 answers
Find the product. (4x²) (–5³)
  • 0 answers
Square of 169
  • 1 answers
(3+i)x + (1-2i) y +7i =0
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App