A cylindrical is within the cube …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Alvin Thomas 3 months ago
- 0 answers
Posted by Yash Pandey 6 months, 1 week ago
- 0 answers
Posted by Savitha Savitha 1 year, 4 months ago
- 0 answers
Posted by Sheikh Alfaz 1 month, 2 weeks ago
- 0 answers
Posted by Akhilesh Patidar 1 year, 4 months ago
- 0 answers
Posted by Duruvan Sivan 6 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Naveen Sharma 8 years, 10 months ago
Ans. Let the length of each edge of the cube is a.
Volume of cube = a3 (1)
Since the Cylinder is within the Cube and it touches all the vertical faces of Cube.
Diameter of Cylinder = a
Radius of base of the cylinder = \(a\over 2\)
Height of Cylinder = a
Volume of Cylinder = \({ {22 \over 7} \times ({a \over 2})^2} \times a = {11 \over 14 }a^3\) (2)
As Cone and Cylinder has same base
Radius of the Cone = \(x \over a\)
Height of Cone = a
Volume of Cone = \({1 \over 3} \times { {22 \over 7} \times ({a \over 2})^2} \times a = {11 \over 42 }a^3\) (3)
Ratio of volumes, From (1) (2) and (3)
=> \( a^3 :{11 \over 14 }a^3:{11 \over 42 }a^3\)
Multiply by 42 and divide by a3, We get
=> 42 : 33 : 11
1Thank You