No products in the cart.

The volume of a sphere is …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

The volume of a sphere is 4851cm.How much should its radius be reduced so that its volume becomes 4312/3cm?

  • 1 answers

Naveen Sharma 8 years, 9 months ago

Ans. Let Initial Radius of Sphere is R and FInal Radius of Sphere is r.

Initial Volume of the sphere = 4851 cm3

=> \({4 \over 3} \times {22 \over 7} \times R^3 = 4851\)

=> \(R^3 = {{4851 \times 21 } \over 88}\)

=> \(R^3 = 1157.625 \)

=> R  = 10.5             (1)

Final Volume of Sphere = \({4312 \over 3} cm^3\)

=> \({4 \over 3} \times {22 \over 7} \times r^3 = {4312\over3}\)

=> \(r^3 = {{4312 \times 7 } \over 88}\)

=> \(r^3 = 343\)

=> r = 7

Radius to be Reduced by = 10.5 - 7 = 3.5 cm

https://examin8.com Test

Related Questions

X³-12x²+39x-28
  • 0 answers
3√2×4√2×12√32
  • 0 answers
2x²+[1×(8x²)^-1]+1
  • 0 answers
What is 38747484±393884747
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App