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An element has bcc structure with …

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An element has bcc structure with a cell of 288 pm. The density of the element is 7.2 g/cm3. How many atoms are present in 208 g of the element?
  • 2 answers

Hitesh Kumar 7 years, 10 months ago

Volume=[288×10^-10]^3 cm^3 ,use this formula D=zM/VN here Z=2 ,M=208,N=?........ your answer is N=24.16×10^23 atoms
1.2×10^7
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