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the frequency of electric feild of …

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the frequency of electric feild of an electromagnetic wave is 2 × 10^10 Hz and the amplitude of its vibration is 48n/m. what is the vlaue of its wavelength ? what is the amplitude of vibration magnetic feild.

    • Posted by Aditi Dhibar 7 years, 10 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Radhika Tyagi 7 years, 10 months ago

    16*10^-8

    0Thank You

    Pema Tanwar 7 years, 10 months ago

    C=frequency*wavelength Wavelength=1.5*10^-2 C=E/B B=E/C =48/3*10^8 15*10^-8

    2Thank You

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