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Two cells of emf 1.5 and …

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Two cells of emf 1.5 and 2.5 having internal resistance 0.2 and 0.3 respectively are connected in parallel . Calculate the emf and internal resistance of the equivalence cell?

    • Posted by Vinit Kumar 7 years, 10 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Yuthika Yadav 7 years, 10 months ago

    Sorry equivalent emf is 1.9

    0Thank You

    Priyanka Aggarwal 7 years, 10 months ago

    ?????????????????

    1Thank You

    Yuthika Yadav 7 years, 10 months ago

    Eeq=E1r2 +E2r1 divided by r1+r2 hence the equivalent emf is 2.1 req=r1r2 divided by r1+r2 hence equivalent resistance is .12

    0Thank You

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