Represent (1+√9.5) on number line

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Neetu Yadav 7 years, 11 months ago
Now extend AB 1 cm more mark that last point as C.
Now take half of the 10.5 cm mark that point O.
Take O as center and draw a semicircle from A to C.
From B draw a perpendicular that intersect semicircle at point D.
Now BD is the value of √9.5, take compass on B open up to D and make an arc on number line,mark it E.
BD= BE= √9.5
Now extend the point D 1 cm upward,mark it N , open compass from B to N draw an arc on number line,that point V.so the length of BV=1+√9.5
2Thank You