Two lines are given to be …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
Equation of a line ax + by + c = 0 parallel to given line is ax + by + k = 0, here k is any real number.
The equation of one line is 4x + 3y = 14.
a1 = 4 , b1 = 3 and c1= - 14
Two lines are given to be parallel. So, No solutions and the pair of linear equations is inconsistent.
{tex}\frac { a _ { 1 } } { a _ { 2 } } = \frac { b _ { 1 } } { b _ { 2 } } \neq \frac { c _ { 1 } } { c _ { 2 } }{/tex}
or
{tex}\frac{4}{{{a_2}}} = \frac{3}{{{b_2}}} \ne \frac{{{c_1}}}{{{c_2}}} {/tex}
{tex}\Rightarrow \frac{{{a_2}}}{{{b_2}}} = \frac{4}{3} = \frac{{12}}{9}{/tex}
Hence, one of the possible, second parallel line is 12x + 9y = 5.
1Thank You