Two vectors both equal in magnitude …
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Sahdev Sharma 8 years, 3 months ago
Let {tex}\theta {/tex} be the angle between the two vectors A and B such that, |A| = |B|.
Therefore, {tex}R ^2 = A ^2 + B ^2 + 2AB cos\theta{/tex}
{tex}=> A^2 = A ^2 + A ^2 + 2AAcos\theta{/tex}
[{tex}\because {/tex} |A| = |B| = |R|]
{tex}=> A^ 2 = 2A^ 2 + 2A ^2 cos\theta {/tex}
{tex}=> cos\theta ={ -1\over 2}\\ => \theta = 120^°{/tex}
2Thank You