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ABCD is a trapezium in which …

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ABCD is a trapezium in which AB parallel to CD.CD is 30cm and AB is 50cm if x and y are the mid points of AD and BC.Prove that ar(DCYX)=7/9ar(XYBA).

Posted by Deepak Agrawal 7 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Hardik Bhardwaj 7 years, 10 months ago

XY= (AB+CD) /2. HEIGHT OF BOTH PARTS IS EQUAL. AREA OF IST PART IS H/2*(AB+XY). AREA OF 2ND IS H/2*(XY+CD). THEIR RATIO IS 7/9.

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CBSE > Class 09 > Mathematics