Sec4x - sec2x = 2
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Mohit Sharma 7 years, 8 months ago
Sec[4x] = 1/(2((2Cos²(x) - 1)² - 1)
Let z = Cos²(x)
Then we have:
1/(2(2z - 1)² - 1) - 1/(2z - 1) = 2
which eventually reduces to the quadratic equation:
16z² - 20z + 5 = 0
with solutions z = (1/8)(5 ± √5)
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