A thief runs with a uniform …
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Posted by Mausam Kumar 7 years, 7 months ago
- 4 answers
Prakhar Chandra 7 years, 7 months ago
As the thief ran 1 min before the police...time taken by the thief before being caught = (n+1) min
Distance travelled by the thief in (n+1) min = 100(n+1)m
Speed of police in 1st min=100m/min
Speed of police in 2nd min=110m/min
...3rd min = 120m/min.........so on
100,110,120,............ this forms an AP
Total distance travelled by the police in n min = n/2(2 x 100 +(n-1)10)
On catching the thief by police,distance traveled by thief= distance travelled by the police
100(n+1)= n/2(2 x 100 + (n-1)10)
100n + 100= 100n +n/2(n-1)10
100=n(n-1)5
n2 -n-20 = 0
(n-5)(n+4) = 0
n-5 = 0
n= 5 OR n= -4...(but this is not possible)
so, n= 5
Time taken by the policeman to catch the thief = 5min
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Anurag Mishra 7 years, 7 months ago
1Thank You