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P and Q are any two points lying on the sides DC and AD represently of a parallelogram ABCD show that ar(APB)=ar(BQC).

Posted by Suchika Roach 7 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Dhruva Parashar 7 years, 10 months ago

ar(APB)=1/2ar(ABCD) [ triangle and llgm lying on same base and b/w same lls] ar(BQC)=1/2ar(ABCD) [same as 1st part] Therefore, ar(APB)=ar(BQC)

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