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If sin(2x +3y)=1 and cos (2x-3y)=√3\2 …

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If sin(2x +3y)=1 and cos (2x-3y)=√3\2 find the value of x and y
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Y B 7 years, 4 months ago

Sin 2x+3y =1 Sin 2x+3y =sin 90 2x+3y=90. eq 1 Now Cos 2x-3y=√3/2 Cos 2x-3y=cos30 2x-3y=30. Eq 2 Adding 2x+3y+2x-3y=90+30 4x=120 X=30. From eq1 2×30+3y=90 60+3y=90 3y=90-60 Y= 10 ie. X=30 ,y=10 answer
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