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7 years ago varun's age was …

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7 years ago varun's age was 5 times the square of Shari's age . 3 years hence swati's age will be 2/5 th of varun's age. Find their present age.
  • 1 answers

Sia ? 6 years, 5 months ago

Let seven years ago Swati's age be x years.
As per given condition
Seven years ago Varun's age was five times the square of Swati's age.
Then, seven years ago Varun's age was 5x2 years.
Therefore, Swati's present age = (x + 7) years
And  Varun's present age = (5x2 + 7) years
Three years hence Swati's age = (x + 7 + 3) years = (x + 10) years
And three years hence Varun's age = (5x2 + 7 + 3) years = (5x2 + 10) years
As per given condition
Three years hence Swati's age will be {tex}\frac{2}{5}{/tex} of Varun's age.
Therefore, x + 10 = {tex}\frac{2}{5}{/tex}(5x2 + 10)
{tex}\Rightarrow{/tex} x + 10 = 2(x2 + 2)
{tex}\Rightarrow{/tex} x + 10 = 2x2 + 4
{tex}\Rightarrow{/tex} 2x2 - x - 6 = 0
{tex}\Rightarrow{/tex} 2x2 - 4x + 3x - 6 = 0
{tex}\Rightarrow{/tex} 2 x ( x - 2 ) + 3 ( x - 2 ) = 0
{tex}\Rightarrow{/tex} (2x + 3) (x - 2) = 0
{tex}\Rightarrow{/tex} x - 2 = 0 [{tex}\because{/tex} 2x + 3 {tex}\neq{/tex} 0 as x > 0]
{tex}\Rightarrow{/tex} x = 2
Hence, Swati's present age = (2 + 7) years = 9 years
Varun's present age = (5 {tex}\times{/tex}22 + 7) years = 27 years

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