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Find Sum of : -    …

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Find Sum of : - 

      8 + 88 + 888 + 8888 +.............

upto n number of terms.

  • 1 answers

Naveen Sharma 8 years, 10 months ago

Ans. S= 8( 1 + 11 + 111 + 1111 + ..... Upto n terms  )

=> 8/9 (9 + 99 + 999 + 9999 + ……… upto n terms)

=> 8/9 [ (10-1) + (100-1) + (1000-1) + upto n terms]

=> 8/9 [ (10 + 100 + 1000 +  ...... n terms ) -(1+ 1 + 1 + ………… n terms)]

=> 8/9 [ 10(10n -1)/ (10-1) - n ]

=> 8/9 [ 10(10n-1)/9 - n]

=> 80(10n -1) /81 - 8n/9

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