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Arg(z-1)=arg(z+3i) then find x-1:y

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Arg(z-1)=arg(z+3i) then find x-1:y
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Ravi Papnai 8 years, 3 months ago

Let z=x+iy X+iy-1=x+iy+3i and (y=imaginary number along with iota and x=constant number I.e 3,4 etc) TanA=y÷x ,tanA=y÷x TanA=y÷x-1 and TanA=y+3÷x (Comparing both sides) Y÷x-1= y+3÷x ( cross multiplication after we get ) 3x-3-y=0 3(x-1)=y X-1÷y=1÷3 (X-1):y=1:3
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