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In a ? ABC, AD bisects …

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In a ? ABC, AD bisects angle A and angle C is greater than angle B prove that angle ADB is greater than angle ADC
  • 2 answers

Swati Sharma 7 years, 10 months ago

Given:- angleC>angleB , angleBAD=angleCAD To prove:- angle ADB > angle ADC Proof:- angle ADB = angle CAD + angle C Angle C= angle ADB - angle CAD (1) angle ADC = angle BAD + amgle B Angle B = angle ADC - angle BAD (2) angle C > angle B From eq (1) and (2) angleADB - angle CAD > angle ADC - angle BAD Cad=bad angleADB > angleADC

Tarun Rana 7 years, 10 months ago

I know answer x
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