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a÷x-a.  +. b÷x-b. =. 2c÷x-c

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a÷x-a.  +. b÷x-b. =. 2c÷x-c

  • 1 answers

Naveen Sharma 8 years, 7 months ago

Ans. a/ x-a + b/x-b  = 2c/x-c

taking (x-a) (x-b) LCM

=> (ax-ab+bx-ab)/(x-a)(x-b) = 2c/x-c

Cross multiply, we get

=> ax2-2abx+ bx2 -acx +2abc-bcx = 2cx2-2acx -2bcx + 2abc

=> ax2 + bx2 -2cx2 = 2abx -acx -bcx

=> (a+b-2c)x2 - (2ab -ac -bc)x = 0

=> x [(a+b-2c)x - (2ab-ac-bc)] = 0

Either x = 0 

Or (a+b-2c)x - (2ab-ac-bc) =0

=> x =(2ab-ac-bc)/(a+b-2c)

 

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