a÷x-a. +. b÷x-b. =. 2c÷x-c
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Naveen Sharma 8 years, 7 months ago
Ans. a/ x-a + b/x-b = 2c/x-c
taking (x-a) (x-b) LCM
=> (ax-ab+bx-ab)/(x-a)(x-b) = 2c/x-c
Cross multiply, we get
=> ax2-2abx+ bx2 -acx +2abc-bcx = 2cx2-2acx -2bcx + 2abc
=> ax2 + bx2 -2cx2 = 2abx -acx -bcx
=> (a+b-2c)x2 - (2ab -ac -bc)x = 0
=> x [(a+b-2c)x - (2ab-ac-bc)] = 0
Either x = 0
Or (a+b-2c)x - (2ab-ac-bc) =0
=> x =(2ab-ac-bc)/(a+b-2c)
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