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The gas phase decomposition of COCl2, …

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The gas phase decomposition of COCl2, COCl2=CO+Cl2 follows the rate law;rate=k[COCl2]^3/2 What are the units of its rate constant?
  • 1 answers

Dr. Kamlapati Bhatt 7 years, 10 months ago

The order of reaction representing rate law  as  ,

Rate  =   k  [ COCl2 ]3/2   is  1.5

The unit for the rate constant  is   M -0.5 s-1 

(where M represents  mole per litre or Molarity of the reactant ) 

   * It should  be noted that even though it is a gas phase reaction , where the change in pressure is conveniently measured during the course of a reaction , but still the rate constant is expressed in terms of change in concentration of the reactant  ( as per rate law ) in terms of moles per Litre (ie .M or molarity ) / unit of time .  The reason being that pressure is temperature as well as  unit dependent , where as concentration or molarity is always in moles per litre .

** The concentration of the reactant is easily calculated using  the relation  PV  =  nRT , or P  = ( n/V ) RT  

ie .   P  =  C RT     

 Explanation : 

THe unit for rate constant of a reaction is derived through dimensional analysis .

In this case since ,

 k  = Rate / [ A ] n 

(where ,  n  represents the order of reaction  

 k =Rate / [ COCl2 ]3/2

or,=  Rate /  [ COCl2 ]1.5

= ( concentration / time )  x  1 / (  concentration )1.5 

= ( mol L-1 ) s-1 x  1 / ( mol L-1 )1.5 

=  [ ( mol L-1 / { mol L-1  ) x ( 1 / mol L-1 )0.5  }s-1 

={ ( 1 / M )0.5 } s -1 

or , =  M -0.5 s-1 

[  where , mol L -1  , represents  molarity (M) of the reactant ]

 

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