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Find the sum of series (2^2+4^2+6^2+8^2+........to …

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Find the sum of series (2^2+4^2+6^2+8^2+........to n terms

    • Posted by Ankit Anand 7 years, 10 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Chandrashekhar Wankhede 7 years, 10 months ago

    nth term of given series = an = square of (2n), Therefore, sn= a1+a2+a3+......+an = 4(sqr(1)+sqr(2)+sqr(3)+......sqr(n)) Using identity , sum of square of n natural numbers = n(n+1)(2n+1)/6 Sn= 4n(n+1)(2n+1)/6

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