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Prove if you can that a …

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Prove if you can that a quadrilateral having one pair of opposite side and one pair of opposite angle equal then it is a parallelogram
  • 31 answers

Jyoti Vaibhaw 7 years, 10 months ago

Please try first and give yourself sometime

Devika Lyju 7 years, 10 months ago

Then u plz do it

Jyoti Vaibhaw 7 years, 10 months ago

Construction is wrong

Jyoti Vaibhaw 7 years, 10 months ago

No not at all

Devika Lyju 7 years, 10 months ago

Is it correct ?

Devika Lyju 7 years, 10 months ago

That is, ABCD is a parallelogram

Devika Lyju 7 years, 10 months ago

We know that the diagonal of a parallelogram divides it into two congruent triangles.Hence the proof

Jyoti Vaibhaw 7 years, 10 months ago

How can a line be parallel to two different lines which are not parallel

Devika Lyju 7 years, 10 months ago

Therefore the triangles r congruent by ASA rule

Jyoti Vaibhaw 7 years, 10 months ago

How can a line be to

Devika Lyju 7 years, 10 months ago

In triangle ABC & CDA, angle B = D,angle BAC = DCA and AB = CD

Devika Lyju 7 years, 10 months ago

Angle BAC = DCA (since AB parallel to CD )

Jyoti Vaibhaw 7 years, 10 months ago

And then?

Devika Lyju 7 years, 10 months ago

Join AC ( diagonal )

Devika Lyju 7 years, 10 months ago

Therefore AB parallel To CD

Devika Lyju 7 years, 10 months ago

Construct EF parallel to AB and CD

Devika Lyju 7 years, 10 months ago

Angle B = D

Devika Lyju 7 years, 10 months ago

<B = < D

Devika Lyju 7 years, 10 months ago

AB = CD

Devika Lyju 7 years, 10 months ago

In which AB = CD & <B = <D

Devika Lyju 7 years, 10 months ago

Consider a quadrilateral ABCD

Devika Lyju 7 years, 10 months ago

Consider a quadrilateral ABCD .let AB = CD and <A = <B.construct EF ll AB and EF ll CD. Therefore, AB ll CD.. Join AC ( diagonal ). Therefore, <BAC = <DCA . In triangle ABC & CDA , <B = < D & AB = CD (given ) & <BAC = <DCA . Therefore the triangles r congruent by ASA.. We know that the diagonal of a parallelogram divides it into two congruent triangles.Hence the proof. ?

Devika Lyju 7 years, 10 months ago

Construct a quadrilateral ABCD with AB = CD & <B = <D.

Devika Lyju 7 years, 10 months ago

Consider a quadrilateral ABCD .let AB = CD and <A = <B.construct EF ll AB and EF ll CD. Therefore, AB ll CD.. Join AC ( diagonal ). Therefore, <BAC = <DCA . In triangle ABC & CDA , <B = < D & AB = CD (given ) & <BAC = <DCA . Therefore the triangles r congruent by ASA.. We know that the diagonal of a parallelogram divides it into two congruent triangles.Hence the proof.

Devika Lyju 7 years, 10 months ago

I 'll try once

Jyoti Vaibhaw 7 years, 10 months ago

Yeah good bt I am also a boy.

Jyoti Vaibhaw 7 years, 10 months ago

Keep trying

Ayush Shekhar Only 7 years, 10 months ago

This is of another kind ....i will try !! Ur question confused me so i love u ?????take this :- kidding

Ayush Shekhar Only 7 years, 10 months ago

Nope . It is of another kind

Jyoti Vaibhaw 7 years, 10 months ago

Krke dekh lo

Ayush Shekhar Only 7 years, 10 months ago

Arrre class 7th ka concept hai ...congruent kr do diagonal draw krke
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