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2.construct trianglePQR where Q= 60 R=30....and …

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2.construct trianglePQR where Q= 60 R=30....and its perpendicualr is 12.5 cm

Posted by Shivendra Kumar Dhamghay 7 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Chandrashekhar Wankhede 7 years, 10 months ago

Let perpendicular height is PS, Draw PS = 12.5 CM horizontally. Construct 90 degree at point S. Extend vertical arm of angle at S on opposite side. Construct 30 degree at point P and allow it to intersect with vertical arm of angle at S. This intersection point will be Q. Similarly construct 60 degree at point P below PS line and allow it to intersect with vertical arm of angle at point S.This intersection point will be R.

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CBSE > Class 09 > Mathematics