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AB is a diameter of a circle, with centre O. If ∠PAB = 55˚, ∠PBQ = 25˚, and ∠ABR = 50˚, find ∠PBA, ∠BPQ and ∠BAR.

Posted by Merlyn Binoy 7 years, 10 months ago

CBSE > Class 09 > Mathematics

1 answers

Bad Gambler 5 years ago

angle ARB=APB=90°(angle subtended by diameter) Angle BAR=Angle ARB+RBA+BAR=180°[angle sum property of triangle] 90+50+BAR=180° 140°+BAR=180° Angle BAR=40° same with ?️ APB ABP+ 55+90=180 ABP+145=180 ABP=35 NOW,Angle PQB=Angle PAB=55°[Angle subtended by same chord] therefore,angle BPQ+PQB+PBQ=180° BPQ+25+55=180 BPQ+80=180 BPQ=180-80 BPQ=100° Therefore,BAR=40°,PBA=35°,BPQ=100°

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CBSE > Class 09 > Mathematics