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Cos4x=1-8sin"xcos" x. ( " squre)

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Cos4x=1-8sin"xcos" x. ( " squre)
  • 1 answers

Yashu Tyagi 7 years, 10 months ago

4x=2×2x let 2x=∆ now, cos2∆=1-2sin"∆ put value of ∆=2x cos4x =1-2(sin 2x)". sin2x =2sinxcosx cos4x =1-2(2sinxcosx)" cos4x =1-2(4sin"xcos"x) cos4x =1-8sin"xcos"x
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