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36x²+12ax+(a²-b²)=0 solved by factorisation method

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36x²+12ax+(a²-b²)=0 solved by factorisation method

Posted by Zoya Jamal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Sajid Alam 3 years, 10 months ago

36x²-12ax+(a²-b²)=0

1Thank You

Shivesh Singh 7 years, 3 months ago

First factorize => (a^2-b^2)= (a+b)(a-b) Now, 36x^2+12ax+(a+b)(a-b)=0 36x^2+6(a+b)x+6(a-b)x+(a+b)(a-b)=0 6x(6x+a+b)+(a-b)(6x+a+b)=0 (6x+a+b)(6x+a-b)=0 Therefore, 6x+a+b=0 and 6x+a-b=0 Hence, x=-(a+b)/6 and x=(b-a)/6

3Thank You

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