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X+y+z=0 show that (x) cube+yxube+z cube=3xyz

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X+y+z=0 show that (x) cube+yxube+z cube=3xyz
  • 1 answers

S Sihag Ji 7 years, 10 months ago

As xcube + ycube + xcube - 3 xyz= ( x+y+x) (xsquare+ ysquare+ zsquare - xy-yz-zx) Xcube+ycube+zcube- 3xyz =0 (xsquare + ysquare + zsquare - xy - yz - zx) Cc xcube+ycube+zcube - 3xyz =0 OR xcube+ycube+zcube = 3xyz
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